Expected Results: A Stable Mana Base

In this tutorial piece, I cover a very fundamental topic in Magic: Mana bases and land counts. Mana is the currency of our favorite card game. If you are interested in casting spells and winning the game, it’s essential to have an adequate amount of mana at every point. Of course, there are some rules of thumb how many mana-producing lands you should play (namely, 17 for limited, or 24 for constructed), but these are just very rudimentary guidelines.

For instance, I had the feeling I struggle to find mana sources too often when playing 17 lands in limited, so I wanted to know the hard facts. Checking Google, I found a number of articles and discussions on this topic, but none of them provided adequate numbers and probabilities.

In this and the following piece, I will illuminate the topic of a proper mana base from different angles. In each, I will define a potential problem concerning the number and distribution of mana-producing lands in your limited deck. After clarifying which aspect I want to discuss, simulation-based results will help us make the right choice to avoid the aforementioned kind of mana problems.

Mana Issues

In Magic you want to be able to cast your spells. Not having enough available mana is the easiest way to fail in this. And it is perhaps the most depressing way to lose a game of Magic. Of course, there is an easy way to avoid this problem: Just put more lands into your deck.

On the other hand, doing so might lead to another problem. Having just mana sources and no spells isn’t much of an improvement. So where is the right balance?

To answer this question using statistics, I have to define the issues more precisely. What about this formulation?:

1. A limited deck plays enough lands if you are consistently able to play one land each turn for up to k turns, where k depends on your strategy, the speed of the format, etc. (In M14 I am usually happy if I am able to play a land every turn up to Turns 4, 5, or even 6, so my k-value for this analysis will be somewhere between 4 and 6. You will have to adjust this for your kind of deck, your strategy, the set you are playing, etc.)

2. A limited deck plays too many lands if it regularly gives you j or more lands in the starting-hand and/or if you are able to play one land each turn for up to i turns.

Again, j and i depend on the format, your strategy, etc.

Usually we would not like to start with 5 or more lands in our opening hand. So I’ve determined that, for our present situation, j is equal to 5.

While I like to play 5 or 6 lands in a row in M14, I would like to avoid playing more than that without missing at least one land-drop. This is because in a typical game, I empty my hand by Turn 6 and would like to draw more spells most of the time from then on. So I set my i-value to 7. (This value would be different if I were playing a different strategy, such as a deck that ran four Garruk’s Hordes. Then I would probably want to consistently play seven lands without missing a land drop.)

Analysis

I performed simulations for decks with 15 to 22 lands per 40 cards total. Each simulation used 1,000,000 games of Magic. For each game, it was counted how many lands we could play in a row without missing a land drop. The results are summarized in the following graph:

Each line represents the probability of hitting a number x land drops in a row when playing the given number of lands in a 40-card deck:

The red line represents the probabilities of being able to play 0, 1, 2, 3, etc., lands in a row without missing a land drop playing 15 lands in a 40-card deck.

The first red bullet is the probability of having a no-land starting hand in a 15-land 40-card deck (we are on the play in this simulation all the time, and we have not mulled it), which is 2.6%.

The second red bullet is the probability of having one land in the starting hand and not drawing a second one by Turn 2. The probability is 8.2%.

Clearly the red line, representing a deck with 15 lands, indicates the highest probability of a no-land starting hand, but of course the chances for a no-land starting-hand are quite small for all scenarios, as all the lines start at a probability between 0% and 3%. Let’s zoom in:

It might seem to be strange that the 15-land deck has a higher probability to play one land compared to the decks with more land, but keep in mind that we are talking about the probability to play one land and then miss the second one!

Overall I think the upper graphs give a bit too much information. Let me provide some simplified scenarios. In a M14-draft I am usually:

1. unhappy to struggle at 0, 1, 2 or 3 lands.
2. happy to play 4, 5 or even 6 lands in a row.
3. unhappy again to play 7 or more lands in a row.

So let us summarize the probabilities for the different scenarios depending on the number of lands played.

Here each bar represents the probability for one of the above scenarios when using a 40-card-deck with the given number of lands.

Not surprisingly the known recommendation of 17 lands seems to be one of the best solutions. The probability of not having at least 4 lands by Turn 4 is relatively low: 29%. The probability of the preferred scenario is the largest of all the analyzed decks (15 to 22 lands): nearly 46%. At the same time the probability for too many lands is reasonably low at around 25%. (Note, of course, that this presumes you haven’t cast any card draw spells or cantrips.)

In my opinion, the comparison of the 17-land deck with the 18-land deck is of special interest.

Starting Hands

I already mentioned that the number of lands in your starting hand is of special interest because opening hands are the only information source you have to decide whether to mulligan. (For example, your opening hand may contain 6 lands, suggesting a mulligan, even though the next six cards are all on-curve spells. This means that some cases in which your first six turns would fall in the “Just right” scenario above could prompt a mulligan, rendering the opening hand even more important to consider.) The decision to mulligan is rarely easy. My approach is to avoid the mulligan as much as possible by minimizing the number of starting hands with too many or too few lands.

To evaluate this, we don’t need simulated results, as the probabilities can easily be calculated. (See Hypergeometric distribution on Wikipedia.)

All probabilities are rounded.

Based on the given table, I feel I am justified in my decision to play 18 lands. The probability for the worst-case scenarios (0 or 1 land and 6 or 7 lands) is 10% (1+7+2+0). That is the lowest probability comparing the 18-lands deck with the 17-lands (12%) and the 16-lands (15%) decks.

Of course, there are always additional factors to consider. For instance, running a number of cantrips or card draw effectively reduces the size of your deck, changing the math. But this will often not be very helpful in your opening hand, when you must make a decision about whether to mulligan before seeing what cards you will cantrip into.

Conclusion

Especially in a slow format like M14, when in doubt, I prefer to have too many lands over missing lands. This is why I play 18 lands all the time in M14. Decreasing the probability for the “not-enough-land” scenario by 6% seems to be good enough for me to accept that I might have too many lands from time to time; in fact, these chances are increased by about only 8%.

Avoiding one kind of mana problem in 6 of 100 games might sound marginal. But are there many 23rd cards that increase the chance to win a game by that much? I don’t think so.

My next article, “The Right Ratio,” will follow a similar approach to find the right ratio of lands in two-color decks. Like this one, it will not revolutionize the way we play Magic, but it will provide some explanation about why we do it the way we do it, when we do it well.

 
  1. And I think everyone has already arrived at the consensus that Theros will be an 18-land deck for limited games because of all the things to do with one’s mana at the high end of the game (bestow and monstrous and activated abilities of gods and equipment)! So this article is another reason to go with 18 land for Theros!

  2. You should be boycotting math, the payout for knowing it is way too low.

    In the end you say: ” Decreasing the probability for the “not-enough-land” scenario by 6% seems to be good enough for me to accept that I might have too many lands from time to time; in fact, these chances are increased by about only 8%.”

    By running 18 lands instead of 17, you decrease the land-screw situation by 6% and increase the flood situation by 8%. Does that not make your deck stumble 2% of the time more often overall?

  3. Not if you have things to sink your mana Into. Just because you flood does not mean you loose. That normally is the opposite when you are short on mana.

  4. If you have mana sinks you are not flooding. The definition of flooding is “Having noticeably more mana than ways of using it,” not “having lots of mana and things to do with it”.

  5. Great article! It’s great to read about probability and simulations for magic games. I just can’t get enough.

    I have one comment about the first graph. I think that graph can also be generated from the hypergeometric distribution. Please correct me if I’m wrong (I’m much better at being wrong than at probability).

    Here’s what I was thinking. A player wants 3 lands by turn 3. If on the play, the player gets two draws meaning we can just look at the probability of drawing three lands in a “starting hand” of 9 cards. That means the probability of drawing 3 lands (and thereby playing 3 lands) is ncoosek(L,3)*nchoosek(40-L, S+D-3)/nchoosek(40,S+T), where L is the number of lands in the deck, S is the number of cards in a starting hand (7), and D is the number of draws (2). For L=16, this comes out to be 25.6%. To obtain the final result, we have to multiply this result by the probability that the player draws a nonland card next, which, for these numbers, is 18/31.

    To completely generalize with a bunch of confusing letters, the probability of playing exactly X lands in a row (i.e. X lands by turn X) is :

    nchoosek(L,K)*nchoosek(C-L,S-1)/nchoosek(C,X+S-1)*(C-L-S+1)/(C-X-S+1)

    where L is the number of lands in the deck, C is the number of cards in the deck, and S is the size of the starting hand. This might be able to be further simplified… (with logic or with identities).

  6. Fascinating analysis — thanks very much! I’m about as far from being a statistician as possible, but I rather love consuming this sort of information when it’s produced by people such as yourself who not only understand it but who are able to render it readily digestible to people like me. Bravo! I thoroughly enjoyed this article, and I eagerly await its sequel.

    By the by, here’s a plug for MTGO Academy contributor Marshall Sutcliffe’s podcast. In an episode from a few months ago, Marshall’s co-host, Brian Wong, does a fine job treating probabilities and the question of splashing cards. How to optimize colored source count for a one card splash, two card splash, etc.? http://lrcast.com/limited-resources-189-mana-bases/

  7. Hey, thanks for all that comments!

    @NoTeef: You are very right. For some reason I thought to complicated and I am so used to solve problems like that by simulation. :-)

    @premiersoupir: Indeed this episode inspired me to write this article!

  8. Thanks for the graphs and probabilities. This may be a necro type comment, but we’re still in the Theros block and I’m brand new to MTGO so I’m sponging as much info as I can in my free time at work :)